Sleuth your slurry

Topics: Chemistry, Solubility, Chemical compound Pages: 12 (2129 words) Published: May 19, 2014
Faith Tuma
Mr. Tuckey
13/05/14
Honours Chemistry 11

Sleuth Your Slurry

Abstract:
This labaratory report shows that when presented with an unknown chemical substance, identification of that substance is revealed through a seires of tests that involve chemical and physical properties of that substance.

Problem:
You are given an unknown chemical substance that you need to be able to identify. How are you going to do this? The compound can be either harmful or toxic, so what you need to do is test all of its physical and chemical properties, and then find out the synthesis of the substance. Qualitative testing and quantitative testing is essential in discovering what the unknown is. _____________________________________________________________________________________________________ Table of Contents

Percipitate test #1…………………………………………………………………………………….…………. 2 Percipitate test #2…………………………………………………………………………………….…………..3 Percipitate test #3………………………………………………………………………………………………...4 Percipitate test #4…………………………………………………………………………………….…………..5 Flame Test #1………………………………………………………………………………………….……………6 pH test #1…………………………………….……………………………………………………………………….7 Physical property test #1...………...…………………………………………………………………………..8 Physical property test #2.………………………………………………………………………………………9 Melting point test #1……………………………………………………………………………………………..10 Conclusion…………………………………………………………………………………………………………….11

Anion Percipitate Test #1
1. For the first percipiate test with my unknown H chemical, I mixed it with , or Lead (III) nitrate. The purpose of this test was to determine whether my unknown formed a percipitate with Lead (III) nitrate, and to eliminate anions. 2. If the reaction with is soluble, it would allow me to narrow down my options to fewer suspected anions. Since only a few anions formed percipitates with Lead (III) nitrate according to my table of solubilities, it would be easier to eliminate anions. 3. This test requires a spot plate cleaned with distilled water and left uncontaminated. Then, after adding 2 drops of to one section of the plate, add 2 drops of unknown H. Record results, and then compare with other suspected anions. This double replacement reaction will yield Pb A and C . It is possible to separate the two chemicals because nitrate is soluble and Lead (III) is not. 4. C= cation A=anion

Pb(NO3)2 + CA PbA3 (ppt) + CNO3 (s)
PbA3 was a faded milky white percipitate.
5. By looking at my table of solubilities, it is possible to eliminate Lead (III) because it formed a percipitate with my unknown. 6. Since I mixed my unknown with Lead (III) nitrate and it formed a percipitate, I am able to conclude it is insoluble. I compared the results with other anions from my table of solubilities, and phosphate’s results (PO4) matched with mine, as well as sulfate (SO4). This helped to narrow down suspected anions.

Anion Percipitate Test #2
1. For this second percipiate test with my unknown H chemical, I mixed it with , or Silver nitrate. The purpose of this test was to determine whether my unknown formed a percipitate with Silver nitrate, and to eliminate anions. 2. If the reaction with is soluble, it would allow me to eliminate suspected anions to get closer to the true anion. Since I eliminated most of the anions in the previous test except for sulfate and phosphate, I attempted to mix my unknown H with silver nitrate and compare them with the results of phosphate and sulfate (seperately) with silver nitrate. 3. This test requires a spot plate cleaned with distilled water and left uncontaminated. Then, after adding 2 drops of to one section of the plate, add 2 drops of unknown H. Record results, and then compare with other suspected anions. This double replacement reaction will yield Ag A and . It is possible to separate the two chemicals because nitrate is soluble and Silver is not. 4. C= cation A=anion

+ CA AgA (ppt) + CNO3 (s)
AgA was a pale-brownish percipitate.
5. By looking at my table of...
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